I've got it backwards... I think the easy way to do it is to calculate the probability that one will not hit:
44/47 * 43/46 * 42/45 * 41/44 * 40/43 * 39/42 * 38/41 * 37/40 * 36/39 * 35/38=
.94 * .93. * 93 * .93 * .93 * .93 * .93 * .93 * .92 * .92 = about 48%
basically .93^10
for 5-handed = about 56%
for 4-handed = about 65%
for 10-handed - about 24%
So it's a crooked coinflip at a 6-handed table -- and that's assuming that opponents play any A.
geez, i was realy tired when i posted that last night.Statistics: Posted by Kuso — Sat Oct 29, 2005 11:31 pm
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