had hit the turn instead of the river. Now I'd figure that I am drawing to 2 potential winning boat outs, if I put villain on the made boat in the first place of course. Will you call an all in there? It's roughly 40 to win 160, the odds are nice, but they're not 2 outer nice.
His calling if your PFR OOP would make me lean towards his having an A, so I'd be thinking that best case here I am going to split if he only has trips like I do. If I boat up on the river I figure an A is a split at best, and I guess you have to figure what the odds are that a 4 or 7 will get you top boat, not loser boat. There's also the chance that he has 55, maybe what, 15% of the time?
Does this math make sense? I'm sure I butchered the crap out of it since I haven't done one of these in a while.
40 to win 160 - 20% equity needed.
1 out (Q) to win 100% of the time - 1 x 1/40 = 2.5%
2 outs (A) to win maybe 20% of the time = .2 x 2/40 = 1%
6 outs (4,7) to win maybe 20% of the time - .2 x 6/40 = 3%
Split the other 40% of the time - .5 x 20% = 10%
Assuming he has no boat and 3 random cards that you don't have he'd have 9 outs to hit on the river - 20% of the time? .2 x 9/40 = 4.5% negative.
If I did this right, you have 16.5% positive equity minus 4.5% negative or 12% - not worth calling a high turn. That's not taking into account the flush cards that could win for him if he has 2 spades, but I'm offsetting that because a high heart on the turn would give you the same possible boost.Statistics: Posted by JDLush — Wed Apr 19, 2006 7:08 am
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