by Aisthesis » Tue Apr 08, 2008 5:54 pm
k3nt, I just realized that I may have misinterpreted your question. Anyhow, it made me start wondering whether my solution really was a Nash equilibrium because it would seem that with no change in EP's strategy, LP could make more by betting [0,37.5%] rather than [0,25%] and [87.5%,1].
I don't think this is the case, because, while the pure bluffs on my suggested optimal strategy only break-even, they do pick up some value on the folds (value they wouldn't have with a check). But let's test it:
On the raises [0,25%] the results are obviously the same. So, we only need to compare what happens on the bets [25%,37.5%] vs. [87.5%,1]. I'm going to normalize the pot to 100 for easy calculation. For easy reference, I'll cal your strategy the value bluff strategy and mine the naked bluff strategy.
1a) LP has [25%,37.5%] on value bluff strategy
EP has [0,25%]: -100, hence -25 weighted
EP has [25%,37.5%]. +50 splitting the original pot, hence +6.25 weighted
EP has [37.5%,50%]. +200, hence 25 weighted.
EP has [50%,1]. 100, hence 50 weighted
Total EV over this range on value bluff strategy: 56.25
1b) LP has [25%,37.5%] on naked bluff strategy (and checks)
EP has [0,25%]: 0
EP has 25%,37.5%]. Again +50 and weighted 6.25
EP has [37.5%,1]. +100, hence weighted 62.5
Total over this range is 68.75.
So, on the value bluff strategy, LP loses 12.50 by betting rather than checking on [25%,37.5%].
How about on the range [87.5%,1]?
2a) value bluff strategy
EP has [0,87.5%]. 0
EP has [87.5%,1]. Split the pot of 100 for EV of 12.50
Total: 12.50
2b) naked bluff strategy
EP has [0,50%]. -100 for EV of -50
EP has [50%,1]. 100 for EV of 50.
Total: 0
So, the total EV for LP is the same on both.