Lets do a little math. The pot is 11SB with me to act with 4 players
left to act behind me.
If I raise and get 2 callers, everyone calls the turn, and 1 player
calls the river the final pot will be 13BB and I will have put in 3BB.
Lets say I call (instead of raise) and get 1 more caller on the flop
and 1 more callers on the turn then the final pot will be the same but
I will have put in 2.5BB.
Probabilities:
- 75%ish of the time there will be a low so value of the low half will be 13 / 2 *.75 = 4.9.
- The value of the top 1/2 will be 13 / 2 * .75 + 13 * .25 = 8.1.
- If there is a low out I will have it 2:3 and 1:3 I will not.
For the raise let R be the % I win the high:
EV = 8.1H + (.66)(4.9) – 3 = 8.1R + .25
For the call let C be the % I win the high:
EV = 8.1H + (.66)(4.9) – 2.5 = 8.1C +.75
That means if 8.1R + .25 = 8.1C + .75 then I will break even with my raise. That will happened whenever 8.1(R – C) = .5 or R – C = .0617
If I have done everything right that a raise would have to win my chance of winning the high by 6% for the raise to be +EV. (It also means that I have a job that allows me to do these calculations instead of doing real work but that a topic for another post).
Does pushing that 1 player out of the pot give me 6% more PE? Add in the fact that a raise puts me in control of the hand, give me the opportunity to get a free card on the turn, gives me good info on what my opponents are playing, and may push more the 1 players out of the pot and I think that the raise is a play that I will continue to make.Statistics: Posted by GooperMC — Mon Jun 06, 2005 7:50 pm
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