odds of AA, KK at 6-max: C(4,2)/C(52,2) * C(4,2)/C(50,2) * P(6,2) = 1 in 1504
odds of AA, KK both flopping sets | AA, KK: C(2,1)/C(48,1) * C(2,1)/C(47,1) * P(3,2) = 1 in 94
so multiply those together to get the odds of AA, KK and both flopping a set: 1 in 141,379
and i guess what you're really asking is what are the odds of [AA, KK at a 6-handed table where both flop a set] happening at least twice in 110 hands.
i get 1 in 3.34M (using binomial stuff against the previous probabilities).
hopefully someone can dbl check that this makes sense.Statistics: Posted by laynegt — Tue Feb 14, 2006 5:15 pm
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