Kent's article is essentially the same formula, but rearranged. So if your chance of winning is n, and the pot is Y and the amount you have to call is X, break-even EV would look like:
n*Y - (1-n)*X = 0
in Aisthesis' formula. So if you solve for n you get
n = X/(Y+X)
which is Kent's formula, for the minimum chance to win that you need to call.
In the example you give, it costs you 10 to play, but you only lose that 10 2/3 of the time, so it really costs you 6.66 to play (hence, the call is 0 EV).
Personally I find it easier to just look at the pot odds I'm getting and the odds against my hand (this is just another version of the same formula). Calling 10 to win 20 is 2:1 pot odds, and 33% chance of winning is 2:1 against my hand. As long as the pot odds are greater than (or equal to) the odds against your hand, calling is correct.Statistics: Posted by Nortonesque — Fri Jun 03, 2005 4:09 pm
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