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I'm not sure your example is conclusive. Gnosis is saying the best way is to use the minimum number of dice; in the case of seven, that would be 2 dice. You're saying to divide the number by 3.5; in the case of seven, that's also 2 dice. So using 7 as an example doesn't seem to tell us much.
Unless, of course, I'm missing something. That happens now and then!
-TW
Statistics: Posted by TightWad — Mon Aug 08, 2005 10:56 am
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i think if you used 7 as an example instead of 6, you will come up with the N/3.5 answer that Rhound and I suggested.
1 die = impossible
2 dice = 6/36 (1/6) ~ 0.17
3 dice = 15/216 (5/72) ~ 0.07
...
7 dice = 1/279936 ~ really small
so by your answer, you are suggesting that 10000/6=1667 is the best answer, but this means that you will only get it 1 out of 6^1667 times. i think the N/3.5 answer is better.
i hope you can prove me wrong... just please do so in layman's terms.
Statistics: Posted by Kuso — Mon Aug 08, 2005 10:35 am
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N is a large number (say 10,000) You need to figure out how many dice you must roll, where the sum of all the dice is N (10,000) - how many dice do you need to maximize your chance of rolling N?
Statistics: Posted by Gnosis — Fri Aug 05, 2005 1:18 pm
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