probability of hitting a set w/ a pp on any given hand, assuming you always play:
p(set) = 1/17 * 1/8.5
therefore the probability of not hitting a set on any given hand:
p(no set) = 1 - p(set)
the prob of not hitting a set in n hands:
p(no set over n hands) = p(no set)^n
so, % to hit no sets over n hands:
10 - 93.3%
50 - 70.7%
100 - 49.9%
500 - 3.1%
10000.10%
13000.012%, or 1 in 8,332Statistics: Posted by laynegt — Fri Aug 19, 2005 10:22 am
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