I was just playing at doylesroom in a $5.00 multitable tournament.

After about 10 minutes, I see this:
3 consecutive hands....
Hand 1: All in preflop - AA vs AK. AA wins, player 1 had AA, player x had AK.
Hand 2: All in preflop - AA vs AK. AA wins, player 1 had AA, player x had AK.
Hand 3: I get AK. I call the blind, player 1 goes all in. I think, what are the odds he could have pocket aces 3 times in a row and go all in preflop against AK 3 times in a row? I thought about it for a second and came up with 1 and a caquadruplegilion ^ 1000000. I called because I had to see it, and of course... I had to play the odds. He had it and I lost.

What are the actual odds of this happening? Assuming player 1 gets the aces all 3 times, and player X gets the AK, and there are 9 people at the table all 3 hands?

Thanks... if anyone can figure this one out.

Player 1 gets aces 3 straight hands: 1 in 221^3 or about 1 in 10.8 million.

Somebody else at the table gets AK at the same time, all three times.

I get a single player catching AK one time when two aces are dead as 0.65%. Multiply
by 9 assuming 9 opponents (which is not quite right, but pretty close) = 5.85%.

5.85% ^ 3 (happens 3 times) = 0.02%, or 2 times in 10,000

So 1 in 10.8 million * 2 in 10,000 = an overall chance of 2 chances in 100 billion. Give or take.

Does this look right?

Looks right, and assuming billions of hands are played every day, these things gotta happen somewhere.

Cool, thanks man. That will actually come in handy figuring out some other things. Like it matters though, when I tried to figure the odds out before playing the hand, I realized the number was going to be huge, so I played it. It's good to know what the real odds are though, and ya, it looks right. Thanks again.